nLab
extensive 2-category

Contents

Idea

The generalization of the notion of extensive category from category theory to 2-category theory.

Definition

A 2-coproduct? A+B in a 2-category is said to be disjoint if we have comma squares

A 2 A B 2 B 0 A 0 B A A+B B A+B B A+B A A+B \array{ A^{\mathbf{2}} & \to & A & \quad & B^{\mathbf{2}} & \to & B & \quad & 0 & \to & A & \quad & 0 & \to & B \\ \downarrow & \Downarrow & \downarrow & \quad & \downarrow & \Downarrow & \downarrow & \quad & \downarrow & \Downarrow & \downarrow & \quad & \downarrow & \Downarrow & \downarrow & \quad\\ A & \to & A+B & \quad & B & \to & A+B & \quad & B & \to & A+B & \quad & A & \to & A+B & \quad}

The first two say that AA+B and BA+B are ff and the second two say that they are disjoint subobjects of A+B.

A coproduct A+B is said to be universal if for any morphism ZA+B, the pullbacks

X Z Y A A+B B\array{X & \to & Z & \leftarrow & Y\\ \downarrow & & \downarrow & & \downarrow\\ A & \to & A+B & \leftarrow & B}

exist and exhibit Z as a coproduct X+Y.

Finally, we say a 2-category is extensive if it has finite coproducts which are disjoint and universal. If it also has finite limits we say it is lextensive, and if it is also coherent we call it positive. (Note that disjoint coproducts in a coherent 2-category are always universal.)

An extensive 2-category does satisfy 2-categorical versions of the additional characterizations of an extensive 1-category, but unlike in the 1-categorical case, these alternate conditions do not seem to suffice to characterize extensivity. In particular, though, a 1-category is extensive as a 1-category iff it is so as a homwise-discrete 2-category.

Properties

Preservation

If K is extensive, so is K co, obviously. Less obvious is:

Lemma

If K is extensive, so are gpd(K), pos(K), and disc(K). In other words, if K is extensive, so is its (n+1)-category trunc n(K) of n-truncated objects for 0n.

Proof

Since the three given categories are closed in K under limits and strict initial objects, it suffices to show they are closed under coproducts. First suppose given two morphisms f,g:ZA 1+A 2. Then f decomposes Z=X 1+X 2, and g decomposes Z=Y 1+Y 2. Then the inclusions X iZ=Y 1+Y 2 also decompose each X i=X i1+X i2. Now if there exists a 2-cell fg, it induces a map from each X ij to the comma object of A 1 and A 2. Since coproducts are disjoint and initials are strict, this implies that X 12=X 21=0. Therefore, we have a decomposition Z=X 11+X 22 so that f=f 1+f 2 and g=g 1+g 2, where f i:X iiA i and g i:X iiA i.

Now, by universality of the coproduct X 11+X 22, it follows that 2-cells fg are determined uniquely by pairs of 2-cells f 1g 1 and f 2g 2. Therefore, if A 1 and A 2 are groupoidal, any 2-cells f 1g 1 and f 2g 2 are invertible, and thus so is any 2-cell fg; so A 1+A 2 is groupoidal. And if A 1 and A 2 are posetal, any parallel 2-cells f 1g 1 and f 2g 2 are equal, and thus so are any fg; so A 1+A 2 is posetal. And of course the discrete case follows by combining these.

However, the (0,1)-category (= poset) Sub(1) of (-1)-truncated objects (= subterminal objects) does not inherit extensivity, and in fact posets are almost never extensive: the only disjoint coproduct is 0+0.

We also have:

Lemma

If K is extensive, so are the fibrational slices Opf(X) and Fib(X) for any XK.

References

This is due to

Created on March 9, 2012 19:29:26 by Urs Schreiber (82.113.106.131)